8520. Conditional statement - 1

Find the value of y according to the following condition:

Input. One integer x (-1000 ≤ x ≤ 1000).

Output. Print the value of y according to the given condition.

Sample input 1	Sample output 1
2	2
Sample input 2	Sample output 2
10	17

SOLUTION

conditional statement

Algorithm analysis

Use a conditional statement to solve the problem. Since -1000 ≤ x ≤ 1000, it’s sufficient to use the int type.

Algorithm implementation

Read the input value of x.

scanf("%d", &x);

Compute the value of y.

if (x < 5)

y = x * x – 3 * x + 4;

else

y = x + 7;

Print the result.

printf("%d\n",y);

Algorithm implementation – ternary operator

Read the input value of x.

scanf("%d", &x);

Compute the value of y.

y = (x < 5) ? x * x – 3 * x + 4 : x + 7;

Print the result.

printf("%d\n",y);

Java implementation

import java.util.*;

public class Main

{

public static void main(String[] args)

{

Scanner con = new Scanner(System.in);

int y, x = con.nextInt();

if (x < 5)

y = x*x - 3*x + 4;

else

y = x + 7;

System.out.println(y);

con.close();

}

}

Python implementation

Read the input value of x.

x = int(input())

Compute the value of y.

if x < 5:

y = x*x - 3*x + 4

else:

y = x + 7

Print the result.

print(y)

Go implementation

package main

import "fmt"

func main() {

var x, y int

fmt.Scanf("%d",&x)

if x < 5 {

y = x*x - 3*x + 4

} else {

y = x + 7

}

fmt.Println(y)

}

C# implementation

using System;

using System.Collections.Generic;

using System.Linq;

using System.Text;

using System.Threading.Tasks;

namespace ConsoleAppCSharp

{

class Program

{

static void Main(string[] args)

{

int x, y;

x = Convert.ToInt32(Console.ReadLine());

if (x >= 5)

y = x + 7;

else

y = x * x - 3 * x + 4;

Console.WriteLine("{0}", y);

}

}

}